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Any BaseSprite instance referred to now always has a texture and a rectangle, which means that it can be drawn without problems. You have been using new in this way ever since your first program. Even this code uses new in the constructor call to set up the Rectangle being used to make the BaseSprite. You can provide as many constructors as you like for a class, so that if there are different ways of providing the initial values, you can provide a constructor for each. You have already seen this in action, too: the Color type provides lots of different constructors so that you can make a new color value in many different ways.

A class-level DataAdapter that has been correctly initialized Dim da As OleDbDataAdapter Sub UpdateRecords() Ensure that conflicting rows don t throw an exception. da.ContinueUpdateOnError = True Send changes to the database, exit if no update conflicts. da.Update(ds, Publishers ) If Not ds.HasChanges Then Exit Sub If we get here, there s at least one conflicting row.

Dim dt As DataTable = ds.Tables( Publishers )

INSERT INTO jobs (job_desc,min_lvl,max_lvl) VALUES ( A new job , 25, 100); _

to 1 and the Vertical setting to 1 . Then click OK. The small graphic jumps to the upper-left corner of the page, displaying its new purple and gray color scheme. (If necessary, move the toolbar to see the image.)

& SELECT job_id FROM jobs WHERE job_id = @@IDENTITY" Dim cmd As New SqlCommand(sql, cn) Insert the new row and read back the IDENTITY field. Dim jobId As Integer = CInt(cmd.ExecuteScalar)

Things become more interesting if you re updating a database table from a DataTable object by means of a DataAdapter and its parameterized InsertCommand and UpdateCommand properties. In this case, you should manually read back the value of an identity

There is a subtle difference in the way that constructors are applied to value types. If you create a constructor for a value type, it must set a value for every data member of the structure:

Part V:

field (in general, a database-generated value) and store it in the proper row and column of the DataTable, so that the new value can be displayed to the user (if the DataTable is bound to a control) or used in relations or calculated fields inside the DataSet. Fortunately, you can have the DataAdapter take this step automatically, without any intervention on your part, thanks to a property of the Command object that I haven t covered yet: the UpdateRowSource property. This property is an enumerated value that can be one of the following: None, OutputParameters, FirstReturnedRecord, or Both. When you use the FirstReturnedRecord value the Command object updates the underlying DataTable with the values from the first row returned by the SELECT com mand. When you use the OutputParameters value the Command object updates the DataTable with the value of all output parameters from a stored procedure. When you use Both (the default value), the Command object updates the DataTable using both the values in the first row returned by the SELECT command and the output parame ters. Let s see how we can use this feature:

Dim jobsTable As DataTable = ds.Tables( jobs )

Troubleshooting If you don t release the selection before clicking the button, the new picture will replace the clip art image.

Dim drow As DataRow = jobsTable.NewRow()

struct demo { int i; int j; int k; public demo(int newi, { i = newi; j = newj; k = newk; } } int newj, int newk)

drow( job_desc ) = A new job"

drow( min_lvl ) = 25

drow( max_lvl ) = 100

dt.Rows.Add(drow)

frame about 4 inches square. (Use the rulers or the size indicator on the status bar to guide you.) When you release the mouse button, Publisher displays the Insert Picture dialog box.

Dim sql As String = _

The structure called demo (which is a value type) contains three data members. If you create a constructor for it, the compiler insists that the constructor must accept some parameters and must explicitly set all three members of the structure. This is not the same as for types managed by reference, where the compiler is much more relaxed about what has been initialized and automatically sets member data to default values (0 for numbers and null for references).

INSERT INTO jobs (job_desc,min_lvl,max_lvl) VALUES (@job_desc, @min_lvl, @max_lvl);